Monthly Archives: November 2015

A student throws a water balloon vertically



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A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower’s hand with a speed of 6.00 m/s. Air resistance may be ignored, so the water balloon is in free fall after it leaves the thrower’s hand.

(a) What is its speed after falling for 2.00 s?

(b) How far does it fall in 2.00 s?
(c) What is the magnitude of its velocity after falling 10.0 m?
(d) Sketch a,-t, v,-t, and y-t graphs for the motion.



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Table 27.5 contains spot and six-month futures prices for severa



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Table 27.5 contains spot and six-month futures prices for several commodities and financial instruments. There may be some money-making opportunities. See if you can find them, and explain how you would trade to take advantage of them. The interest rate is 14.5 percent, or 7 percent over the six-month life of thecontracts.



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Chemical Kinetics Rate Laws,



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I am trying to determine the value of k in the following equation r = k [A]^m [B]^n
r = 1.30×10^-3 mol/(L x s) –> moles per liters per second
[A] = 0.0150 mol/L
m= 2
[B] = 0.025 mol/L
n= 1
therefore 1.30 x 10^-3 mol/(L x s) = k (0,0150mol/L)^2 (0.250mol/L)
therefore k = [1.30 x 10^-3 mol/(L x s) ] / (0.015mol/L)^2 (0.0250mol/L)
How do I know the units to use for k ? for example s^-1 or L^2/(mol^2 x s)



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